//Copyright-Author: Morris Ng function fnDefragChecCaIcProced(){ document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("") document.writeln("


Step 1		Starting from number system character \(NSC\) add all the character values in odd-numbered positions.
		0		1	2	3	4	5		6	7	8	9	0		?

		0		+	2	+	4	+		6	+	8	+	0			\(sum\)	=	20

Step 2		Multiply the sum in step 1 by constant value \"3\".

		20 x 3															\(product\)	=	60

Step 3		Add all the character values in even-numbered positions.
		0		1	2	3	4	5		6	7	8	9	0		?

				1	+	3	+	5		+	7	+	9				\(sum\)	=	25

Step 4		Add the product in step 2 and the sum in step 3.

		60 + 25															\(sum\)	=	85

Step 5		If the sum in step 4 is a multiple of 10, the check digit is \"0\" \(zero\). Else, subtract the sum in step 4 from the next highest multiple of 10 \(i.e., the highest multiple of 10 next to the sum in step 4 is 90\).

		90 - 85															\(difference\)	=	5

																			^ \| \|
Check Digit

")}